The general electronic configuration of the outer most and penultimate shell for a `d-`block element is given by `(n-1)s^(2)p^(6)d^(x)ns^(y)`. For an element if `n=4`, `x=6`, `y=2` then the number of protons in its divalent cation are `a` then `a/(13)` equals to

Write the general outer electronic configuration of s- , p- , d- and f-block elements.

Outer electronic configuration of an element is 4s13d10. The element is expected to be

Elements with outer electron configuration ns2 np6 are:

An atom of an element X has 2 electrons in its N shell. State the number of protons in X.

The electronic configuration of an element is 1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^1 . This represents its

The electronic configuration of Ni (atomic number =28 ) is given as [Ar]4s^(2)3d^(y) .The value of y is

In the general electronic configuration (n-2)^f(1-14) (n-1)^d(0-1) ns^2 ,if the value of n=7,the configuration will be of

The transition element ( with few exceptions ) show a large number of oxidation states . The various oxidation states are related to the electronic configuration of their atoms. The variable oxidation states of a transition metal is due to the involvement of (n-1)d and outer ns electrons . For the first five elements of 3d transition series , the minimum oxidation state is equal to the number of electrons in 4s shell and the maximum oxidation state is equal to the sum of 4s and 3d electrons. The relative stability of various oxidation states of a given element can be explained on the basis of stability of d^(0),d^(5) and d^(10) configuration . In 3d series, the maximum oxidation state is shown by

The transition element ( with few exceptions ) show a large number of oxidation states . The various oxidation states are related to the electronic configuration of their atoms. The variable oxidation states of a transition metal is due to the involvement of (n-1)d and outer ns electrons . For the first five elements of 3d transition series , the minimum oxidation state is equal to the number of electrons in 4s shell and the maximum oxidation state is equal to the sum of 4s and 3d electrons. The relative stability of various oxidation states of a given element can be explained on the basis of stability of d^(0),d^(5) and d^(10) configuration . In which of the following pairs , the first species is more stable than second one

The transition element ( with few exceptions ) show a large number of oxidation states . The various oxidation states are related to the electronic configuration of their atoms. The variable oxidation states of a transition metal is due to the involvement of (n-1)d and outer ns electrons . For the first five elements of 3d transition series , the minimum oxidation state is equal to the number of electrons in 4s shell and the maximum oxidation state is equal to the sum of 4s and 3d electrons. The relative stability of various oxidation states of a given element can be explained on the basis of stability of d^(0),d^(5) and d^(10) configuration . Identify the correct statement