If `x/(b+c-a)=y/(c+a-b)=z/(a+b-c)` then `(b-c)x+(c-a)y+(a-b)z` is
`(a) 1`
`(b) 0`
`(c) 5`

If (x)/(b+c-a)=(y)/(c+a-b)=(z)/(a+b-c) show that (b-c)x+(c-a)y+(a-b)z=0

If (x)/(b + c - a) = (y)/(c + a - b) = (z)/(a + b - c) , then value of x(b -c) + y(c -a) + z(a - b) is equal to

L_1=(a-b)x+(b-c)y+(c-a)=0L_2=(b-c)x+(c-a)y+(a-b)=0L_3=(c-a)x+(a-b)y+(b-c)=0 KAMPLE 6 Show that the following lines are concurrent L1 = (a-b) x + (b-c)y + (c-a) = 0 12 = (b-c)x + (c-a) y + (a-b) = 0 L3 = (c-a)x + (a-b) y + (b-c) = 0. ,

If x=b-c+a, y=c-a+b, z=a-b+c , then prove that (b-a) x + (c-b)y +(a-c)z=0

If 2b = a + c and y^(2) = xz , then what is x^(b-c) y^(c-a)z^(a-b) equal to ?

If (a)/(x)+(y)/(b)=1 and (b)/(y)+(z)/(c)=1, then (x)/(a)+(c)/(z) will be equal to: (a) 0 (b) (b)/(y) (c) 1 (d) (y)/(b)