Solve `sin^(2)n theta-sin^(2) (n-1) theta=sin^(2) theta`.

Solve the equation sin^(2)ntheta - sin^(2)(n-1)theta = sin^(2)theta

sin^2 n theta- sin^2 (n-1)theta= sin^2 theta where n is constant and n != 0,1

Solve it sin((k+1)/2)theta-sin((k-1)/2)theta=sintheta

Solve: 2sin^(2)theta+sin^(2)2theta=2

Solve: 2sin^(2)theta+sin^(2)2theta=2

Prove that sin^2 theta+sin^2 2theta+sin^2 3theta+....+sin^2 n theta=n/2-(sin n theta cos(n+1)theta)/(2sin theta)

Solve sin 3 theta-sin theta=4 cos^(2) theta-2 .

Solve sin 6 theta=sin 4 theta-sin 2 theta .

Solve: sin3theta=sin2theta

Solve: sin2theta=sin((2pi)/(3)-theta)