Solve the equation and find the value of x :

`4^( x - 1 ) - 3 . 2^( x - 1 ) + 2 = 0`

In the following question, two equations are given. You need to solve these equations and find out the value of x and y and give an answer x^2 + 3x + 2 = 0 y^2 + 3y- 4 = 0

Solve 16x^4-1 =0. Find the value of x

Find the value of x , | [ x , 4 ,-4 ], [ 3 , -2 , 1 ] , [ -2 , 4 , 1 ] | = 0

Solve the equation 4sin x cos x+2sin x+2cos x+1=0

Solve the equation 2|x-2|-3|x+4|=1

Solve the equation x^(2)-4x+[x]+3=0

Solve the equation |2x-1|=3[x]+2{x}

Find the values of x for which (x^(2)-4x+3)/(x^(2)+x+1)<0

Let the equation x^(5) + x^(3) + x^(2) + 2 = 0 has roots x_(1), x_(2), x_(3), x_(4) and x_(5), then find the value of (x_(2)^(2) - 1)(x_(3)^(2) - 1)(x_(4)^(2) - 1)(x_(5)^(2) - 1).

Solve the equation for x:x^(5)+x^(4)+x^(3)+x^(2)+x+1=0