`frac{sin^2theta}{1-sin^2theta}=3`

(1+tan^2theta) sin^2theta

If sintheta+sin^2theta=1, then prove that cos^(12)theta+3cos^(10)theta+3cos^8theta+cos^6theta-1=0 Given that sintheta=1-sin^2theta=1-sin^2theta=cos^2theta

Prove that (1+sin 2theta)/(1-sin 2theta) = ((1+tan theta)/(1-tan theta))^2

Prove that cos^6 theta+ sin^6 theta= 1-3sin^2 theta cos^2 theta

Solve: sin3theta=sin2theta

Prove the following identity: (1/(sec^2theta-cos^2theta)+1/(cos e c^2theta-sin^2theta))sin^2thetacos^2theta=(1-sin^2thetacos^2theta)/(2+sin^2thetacos^2theta)

Prove the following identity: (1/(sec^2theta-cos^2theta)+1/(cos e c^2theta-sin^2theta))sin^2thetacos^2theta=(1-sin^2thetacos^2theta)/(2+sin^2thetacos^2theta)

Prove that (1+sin2theta)/(1-sin2theta)=((1+tantheta)/(1-tan theta))^(2)

Prove that sin^2 theta+sin^2 2theta+sin^2 3theta+....+sin^2 n theta=n/2-(sin n theta cos(n+1)theta)/(2sin theta)

If costheta+cos^2theta=1, Prove that: sin^(12)theta+3sin^(10)theta+3sin^8theta+sin^6 theta+2sin^4 theta+2sin^2theta-2=1