consider the parabola with vertex (1/2,3/4) and the directrix y=1/2.Let P be the point where the par

Find the equation of the parabola with vertex is at (2,1) and the directrix is x=y-1.

Find the equation of a parabola with vertex at the origin and the directrix, y=2.

Equation x^2 - 2x - 2y + 5 = 0 represents (A) a circle with centre (1, 1) (B) a parabola with vertex (1, 2) (C) a parabola with directrix y= 5/2 (D) a parabola with directrix y= - 1/3

Find the equation of parabola whose focus is (0,1) and the directrix is x+2=0. Also find the vertex of the parabola.

Statement-1: Length of the common chord of the parabola y^(2)=8x and the circle x^(2)+y^(2)=9 is less than the length of the latusrectum of the parabola. Statement-2: If vertex of a parabola lies at the point (a. 0) and the directrix is x + a = 0, then the focus of the parabola is at the point (2a, 0).

The equation of the parabola with focus (1,-1) and directrix x + y + 3 = 0, is

If the focus is (1,-1) and the directrix is the line x+2y-9=0, the vertex of the parabola is

The equation of the parabola with vertex at origin and directrix the line y + 3 = 0 is

Consider the parabola x^(2) +4y = 0 . Let P(a,b) be any fixed point inside the parabola and let S be the focus of the parabola. Then the minimum value at SQ +PQ as point Q moves on the parabola is (a) |1 -a| (b) |ab|+1 (c) sqrt(a^(2)+b^(2)) (d) 1-b

If the focus of a parabola is (-2,1) and the directrix has the equation x+y=3 then its vertex is a. (0,3) b. (-1,1/2) c. (-1,2) d. (2,-1)