For the figure -
(A)`A+B=C`
(B)`B+C=A`
(C)`C+A=B`
(D)`A+B+C=0`

In triangle ABC (Figure), which of the following is not true: (A) -> A B+ -> B C+ -> C A= ->0 (B) -> A B+ -> B C- -> A C= ->0 (C) -> A B+ -> B C- -> C A= ->0 (D) -> A B- -> C B+ -> C A= ->0

In a triangle A B C , right angled at B , the inradius is (A B+B C-A C)/2 (b) (A B+A C-B C)/2 (A B+B C+A C)/2 (d) none

If in two triangles A B C and D E F , (A B)/(D E)=(B C)/(F E)=(C A)/(F D) , then F D E C A B (b) F D E A B C (c) C B A F D E (d) B C A F D E

In Figure, A B_|_B E\ a n d\ F E\ _|_B Edot If B C=D E\ a n d\ A B=E F , then A B D is congruent to: E F C (b) E C F (c) C E F (d) F E C

In Fig. 10.78, if A D , A E and B C are tangents to the circle at D , E and F respectively. Then, (FIGURE) A D=A B+B C+C A (b) 2A D=A B+B C+C A (c) 3A D=A B+B C+C A (d) 4A D=A B+B C+C A

In Figure, it is given that A B=B C and A D=E C . Prove that A B E~=C B D

In figure A B=A C\ a n d\ C P||B A and A P is the bisector of exterior /_C A D of A B C . Prove that /_P A C=/_B C A (ii) A B C P is a parallelogram

Which two figure have an equal area? (FIGURES) A and B( b) B and D(c)A and C (d) A and D

In Figure, A B C is an isosceles triangle in which A B=A CdotC P A B and A P is the bisector of exterior /_C A D of A B C . Prove that /_P A C=/_B C A and (ii) A B C P is a parallelogram.

If a,b,c are in both : A.P. and G.P. then (A) a=b!=c (B) a!=b=c (C) a!=b!=c (D) a=b=c