`(costheta+sintheta)/(sintheta-costheta)=3/5`

The distance between the points (costheta,sintheta) and (sintheta,-costheta) is

Find the inverse of the matrix [(costheta ,sintheta) ,( -sintheta ,costheta )] .

Choose the correct answer from the following : The value of |{:(-costheta,sintheta),(-sintheta,-costheta):}| is:

Prove that : (1-costheta)/(sintheta)+(sintheta)/(1-costheta)=2"cosec "theta

If for the matrix A=[(costheta, 2sintheta),(sintheta,costheta)],A^(-1)=A^(T) then number of possible value(s) of theta in [0, 2pi] is :

Show that costheta.[{:(costheta,sintheta),(-sintheta,costheta):}]+sintheta.[{:(sintheta,-costheta),(costheta,sintheta):}]=I.

Simplify the following : cos theta [{:(costheta,-sintheta ),(sintheta,costheta ):}]+sintheta[{:(sintheta,costheta),(-costheta,sintheta):}]

costheta[{:(costheta,-sin theta),(sintheta,costheta):}]+sintheta[{:(sintheta,costheta),(-costheta,sintheta):}]=?

(1+costheta+sintheta)/(1+costheta-sintheta)=(1+sintheta)/(costheta)

Simplify: cos theta[{:(costheta,sintheta),(-sintheta,costheta):}]+sintheta[{:(sin theta ,-costheta),(costheta, sintheta):}]