The minimum strength of a uniform electric field which can tear a conducting uncharged thin-walled sphere into two parts is known to be `E_(0)` .Determine the minimum electric field strength `E_(1)` required to tear the sphere of twice as large radius if the thickness of its walls is the same as in the former case

A proton of mass m and accelerated by a potential difference Vgets into a uniform electric field of a parallel plate capacitor parallel to plates of length 1 at mid-point of its separation between plates. The field strength in it varies with time as E = at, where a is a positive constant. Find the angle of deviation of the proton as it comes out of the capacitor. (Assume that it does not collide with any of the plates.)

A uniform electric field in positive x -direction on exists in space. An uncharged solid conducting sphere is now placed in region of this uniform electric field. The centre of this sphere of radius R lies at origin. Then electric potential at any point on y-z plane (i.e. x=0 plane) due to only induced charged on surface of sphere.

A uniform electric field in positive x -direction on exists in space. An uncharged solid conducting sphere is now placed in region of this uniform electric field. The centre of this sphere of radius R lies at origin. Then electric potential at any point on y-z plane (i.e. x=0 plane) due to only induced charged on surface of sphere.

Two concentric conducting thin shells of radius R and 2 R carry charges +Q and +3Q respectively. The magnitude of electric field at a distance x outside and inside from the surface of outer sphere is same. Then the value of x is

A particle of mass m carries an electric positive charge Q and is subjected to the combined action of gravity g and a uniform horizontal electric field of strength E ,it is projected with speed u to the vertical plane parallel to the electrical field and at an angle theta to the horizontal .The maximum distance the particle travels horizontally when it is at the same level as its starting point is

A velocity filter uses the properties of electric and magnetic field to select particles that are moving with a specifice velocity. Charged particles with varying speeds are directed into the filter as shown. The filter consistt of an electric field E and a magnetic field B, each of constant magnitude, directed perpendicular to each other as shown, The charge particles will experience a force due to electric field given by F = qE. If positively charged particles are used, this force is towards right. The moving particle will also experience a force due to magnetic field given by F = qvB . When forces due to the two fields are of equal magnitude, the net force on the particle will be zero, the particle will pass through centre with its path unaltered. The electric and magnetic fields can be adjusted t choose the specific velocity to be filtered. The efect of gravity can be neglected. The electric and magnetic fields are adjusted to detect particles with positive charge q of certain speed v_(0) . which of the following expressions is equal to this speed?

A velocity filter uses the properties of electric and magnetic field to select particles that are moving with a specifice velocity. Charged particles with varying speeds are directed into the filter as shown. The filter consistt of an electric field E and a magnetic field B, each of constant magnitude, directed perpendicular to each other as shown, The charge particles will experience a force due to electric field given by F = qE. If positively charged particles are used, this force is towards right. The moving particle will also experience a force due to magnetic field given by F = qvB. When forces due to the two fields are of equal magnitude, the net force on the particle will be zero, the particle will pass through centre with its path unaltered. The electric and magnetic fields can be adjusted t choose the specific velocity to be filtered. The efect of gravity can be neglected. If the filter is set to detect particles of speed v_(0) , which one of the following diagrams best illustrates how the magnitude of the particle acceleration (a) depends on velocity v?

An electron accelerated by a potential difference V= 3 volt first enters into a uniform electric field of a parallel plate capacitor whose plates extend over a length l= 6 cm in the direction of initial velocity. The electric field is normal to the direction of initial velocity and its strength varies with time as E= alpha t, where alpha= 3600 V m^-1 s^-1. Then the electron enters into a uniform magnetic field of induction B = pi xx 10^-9 T. Direction of magnetic field is same as that of the electric field. Calculate pitch of helical path traced by the electron in the magnetic field. (Mass of electron, m = 9 xx 10^-31 kg )

An infinitely large layer of charge of uniform thickness t is placed normal to an existing uniform electric field. The charge on the sheet alters the electric field so that it still remains uniform on both the sides of the sheet and assumes values E_1 and E_2 as shown in figure. The charge distribution in the layer is not uniform and depends only on the distance from its faces. Find the expressions for the force F per unit experienced by the charge layer.

Two large thin conducting plates with a small gap in between are placed in a uniform electric field E (perpendicular to the plates.)The area of each plate is A, and charges +Q and -Q are given to these plates as shown in figure. If R,S, and T are three points in space, then the