If `(2x+y+2)/(5)=(3x-y+1)/(3)=(3x+2y+1)/(6)` then "

6/(x+y)=7/(x-y)+3 , 1/(2(x+y))=1/(3(x-y))

Find the value of x and y (1)/(2x)+(1)/(3y)=2 (1)/(3x)+(1)/(2y)=(13)/(6)

If 2^(x+y) = 6^(y) and 3^(x-1) = 2^(y+1) , then the value of (log 3 - log 2)//(x-y) is

(5)/(8)x+(7)/(2)y=(3)/(2) (1)/(6)x-(2)/(3)y=1 If the ordered pair (x, y) satisfies the system of equations above, what is the sum of the values of x and y?

{:(3x - 2y = 6),((x)/(3) - (y)/(6) = (1)/(2)):}

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line (1) (x+3)/3=(y-5)/1=(z-2)/(-5) (2) (x+3)/(-3)=(y-5)/(-1)=(z+2)/5 (3) (x-3)/3=(y+5)/1=(z-2)/(-5) (3) (x-3)/(-3)=(y+5)/(-1)=(z-2)/5

{:(x - 2y = 5),(3x - 6y = 15):}

{:(3x - y = 5),(6x - 2y = 10):}

1/(3x+y) + 1/(3x-y) = 3/4 1/(2(3x+y)) - 1/(2(3x-y)) = -1/8

Solve for x and y : (y+7)/(5)=(2y-x)/(4)+3x-5 (7-5x)/(2)+(3-4y)/(6)=5y-18