`tan^-1[cosx/(1+sinx)],dy/dx`=

tan^-1((1+cosx)/(sinx))

Differentiate the following functions with respect to x : tan^(-1){(cosx)/(1+sinx)},0ltxltpi

Express each of the following in the simplest form: tan^(-1){(cosx)/(1-sinx)} ,where -pi/2 < x < pi/2 (ii) tan^(-1)((cosx-sinx)/(cosx+sinx)) , -pi/4 < x < pi/4

Differentiate the following functions with respect to x : tan^(-1){(cosx)/(1+sinx)} , 0 < x < pi

Differentiate tan^(-1){(cosx)/(1+sinx)},\ 0 le x le pi

If y=tan^(-1)((1-cosx)/(sinx)), then (dy)/(dx) is

Find dy/dx , tan^(-1){(cosx - sinx)/(cosx + sinx)} .

Find (dy)/(dx) for y=tan^(-1){(1-cosx)/(sinx)},-piltxltpi .

Find the derivative of tan^(-1)((cosx - sinx)/(cosx + sinx)) with respect to 'x'

Differentiate tan^(-1)((cosx)/(1+sinx)) with respect to sec^(-1)xdot