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cos m theta=sin n theta...

`cos m theta=sin n theta`

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5. sin m theta=sin n theta

If A=[[cos theta,sin theta-sin theta,cos theta]] then prove that A^(n)=[[cos n theta,sin n theta-sin n theta,cos n theta]],n in N

Prove that ((1+cos theta+i sin theta)/(1+cos theta-i sin theta))^(n)=cos n theta+i sin n theta

If A=[cos theta i sin theta i sin theta cos theta], then prove by principle of mathematical induction that A^(n)=[cos n theta i sin n theta i sin n theta cos n theta] for all n in N.

(sin4 theta+sin5 theta)/(cos3 theta+1)=sin(m theta)+sin(n theta) where m,n in N, then (m+n) equals.

If cos ec theta-sin theta=m and sec theta-cos theta,=n, eliminate theta

if cos ec theta-sin theta=m and sec theta-cos theta=n, eliminate theta

[(1 + cos theta + i sin theta) / (sin theta + i (1 + cos theta))] ^ (4) = cos n theta + i sin n theta

(cos theta + i sin theta) ^ (n) = cos n theta + i sin n theta

If theta in R - {(4n + 1) pi/4 , n in I} , then range of (cos 3 theta + sin 3 theta)/(cos theta - sin theta) is :