(a) `4/15+5/15+1/15=`

The fractional part of 2^(4n)/15 is (n in N) (a) 1/15 (b) 2/15 (c) 4/15 (d) none of these

The fractional part of 2^(4n)/15 is (n in N) (A) 1/15 (B) 2/15 (C) 4/15 (D) none of these

Solve : 0/(15)+2/(15)+1/(15)

The probability that a number selected at random from the numbers 1,\ 2,\ 3,\ dot,\ 15 is a multiple of 4, is 4/(15) (b) 2/(15) (c) 1/5 (d) 1/3

The fraction to be added to 6 7/(15) to get 8 1/5 is equal to (a) (11)/(15) (b) 1 1/(15) (c) (44)/3 (d) 3/(44)

Solve : (a) 1/18+1/18 (b) 8/15 + 3/15 (c) 7/5-5/7 (d) 1/22 + (21_/(22) (e) (12)/(15) -(7)/(15) (f) 5/8 + 3/8 (g) (1) - 2/3 (1=3/3) (h) 1/4 + 0/4 (i) (3) -(12)/5

(3^(-1)xx5^(-1))^(-1) = (a) 1/(15)\ \ \ (b) -1/(15) (c) 15 (d) -15

Subtract: 4/(15)\ from \ 2 1/5

With usual notations prove that C_1/C_0 + 2. C_2/C_1 + 3.C_3/C_2 + ……+n.(C_n)/(C_(n-1)) = (n(n +1))/(2) Hence prove that (15C_1)/(15C_0) + 2.(15C_2)/(15C_1) + 3. (15C_3)/(15C_2) +……..+ 15. (15C_15)/(15C_14) = 120

What should be added to 5 4/(15) to get 12 3/5?