The value of `1frac(4)(11) div{[frac(11)(80) div frac(3)(4)div (frac(1)(4) - frac(1)(3) xx frac(1)(5)) div 1frac(5)(6)]+frac(9)(11)}`is

14 frac(3)(4)-12 frac(1)(6) xx 3frac(1)(8)+6frac(3)(12)- 3 frac(1)(2)=

HCF of frac(2)(3) , frac(4)(5) and frac(6)(7) is

Find the value of 3 frac(1)(4) div 5frac(1)(2)(1-frac(1)(4))

The median of the date 1, frac(1)(2) , frac(1)(2) , frac(3)(4) , frac(1)(4) , 2, frac(1)(2) , frac(1)(4) , frac(3)(4) is

1 + frac(1)(2) + frac(1) (4) + frac(1)(7) + frac(1)(14) + frac(1)(28) is equal to

The value of frac(2frac(1)(3) xx 4frac(1)(4) -4frac(1)(6) + 6 frac(1)(4)) (3frac(1)(3) + 4frac(1)(4) xx 5frac(2)(3)) is (A) 21frac(1)(160) (B) 2frac(13)(160 (C ) 2frac(21)(160) (D) frac(7)(1000)

Simplfy frac(2frac(3)(4) (frac(5)(6) div frac(7)(8) xx (frac(1)(3)+ (1)/(4) + frac(5) (7) div frac(3)(4) of frac(3)(7)))

. Add frac(-2)(3) and frac(3)(4).

EXAMPLE 1. Simplify: (i) frac(7)(15) div frac(2)(3) (ii) frac(-8)(35) div frac(2)(7) (iii) frac(16)(21) div frac(-4)(3) (iv) frac(-9)(20) div frac(-3)(10)

Find the values of frac(1)(2) + frac(1)(6) + frac(1)(20)+frac(1)(30)