If `y^2=x^y` then `dy/dx=?`

If x^2+y^2=x-y find dy/dx

If x+y=2^(y), then (dy)/(dx) equals-

If log((x^2-y^2)/(x^2+y^2))=a , then dy/dx=?

If x^2y^2=(x+y)^5 then find dy/dx

If 2^x-2^y=2^(x+y) then dy/dx= (a) (2^x+2^y)/(2^x-2^y) (b) (2^x+2^y)/(1+2^(x+y)) (c) (2^(x-y))(1-2^y)/(2^x+1) (d) (2^x-2^y)/(2^x+2^y)

If x^(y) = 2^(x-y) , then (dy)/(dx) =?

If sqrt(a^(2)-x^(2))+sqrt(a^(2)-y^(2))=k(x-y) then (dy)/(dx)=

If 2^x+2^y=2^(x+y) then (dy)/(dx)

If log_(10)((x^(2)-y^(2))/(x^(2)+y^(2)))=2 , then (dy)/(dx)=

If cos^(-1) ((x^(2) -y^(2))/( x^(2)+y^(2)))=a ,then (dy)/(dx) =