`(4^(1/3))times[2^(1/3)times3^(1/2)]divide9^(1/4)=`

Show ((-8)/(7))times[(1)/(2)times((-4)/(3))]=[((-8)/(7))times(1)/(2)]times((-4)/(3))

Find : (8^(-1)times(5)^(3))/(2^(-4))

Evaluate: (-2) times (-3) times (-1) times (-4) times (-7)

Find the value of. (i) (3^@+4^(-1)) xx 2^2 (ii) (2^(-1)xx 4^(-1))-: 2^(-1) (iii) (1/2)^-2 + (1/3)^-2 + (1/4)^-2 (iv) (3^-1 + 4^-1+ 5^(-1))^0 (v) {((-2)/3)^-2}^2

Prove that: (2^(1/2)\ xx\ 3^(1/3)\ xx\ 4^(1/4))/(10^(-1/5)\ xx\ 5^(3/5))\ -:(3^(4/3)\ xx\ 5^(-7/5))/(4^(-3/5)\ xx\ 6)=10

Evaluate : [(-(2)/(3))^(-2)]^(3)xx((1)/(3))^(-4)xx3^(-1)xx(1)/(6)

Prove that: 3^(1/2)xx3^(1/4)xx3^(1/8)xx...=3

Simplify : (4^(-1)xx\ 3^(-1))^2 (ii) (5^(-1)-:6^(-1))^3 (iii) (2^(-1)+\ 3^(-1))^(-1) (iv) (3^(-1)xx\ 4^(-1))^(-1)xx\ 5^(-1)

Simplify (i) {(1/3)^(-2) - (1/2)^(-3)} -: (1/4)^(-2). (ii) (5/8)^(-7) xx (8/5)^(-5).

(2)/(1).(1)/(3)+(3)/(2).(1)/(9)+(4)/(3).(1)/(27)+(5)/(4).(1)/(81)+…oo=