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A line y=mx+1 meets the circle (x-3)^(2)...

A line y=mx+1 meets the circle `(x-3)^(2)+(y+2)^(2)=25` at point P and Q. if mid point of PQ has abscissa of `-(3)/(5)` then value of m satisfies

A

`-3 le m lt -1`

B

`2 le m lt 4`

C

`4 le m lt 6`

D

`6 le m lt 8`

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