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Three lines are given by r=lambda hati...

Three lines are given by
`r=lambda hati, lambda in R`
`r=mu(hati +hatj ),mu in R`
and `r=v(hati+hatj+hatk),v in R`
Let the lines cut the plane `x+y+z=1` at the poitns A, B, and C respecitvely . If the area of the tiangle ABC is `Delta` then the value of `(6Delta)^2` equals..............

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Three lines L_1:r=lambda hat i, lambda in R, L_2: r=hatk+muhatj,mu in R and L_3:r=hati+hatj+vhatk,v in R are given , for which points (s) Q on L_2 can we find a point, P on L_1 and a point R on L_3 so that P,Q and R are collinear ?

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Equation of three lines vecr=lamdahati,vecr=mu(hati+hatj),vecr=gamma(hati+hatj+hatk) and a plane x+y+z=1 are given then area of triangle formed by point of intersectioin of line and plane is Delta then (6Delta)^(2) equals

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