The distance of the point `P(x_0, y_0, z_0)` from z - axis

What is the distance of the point (x, y, z) from x-axis?

In three dimensional spaces, the perpendicular distance of the point p (x,y,z) from the Y-axis is-

If the sum of the squares of the distances of the point (x, y, z) from the points (a, 0, 0) and (-a, 0, 0) is 2c^(2) , then which are of the following is correct?

If the sum of the squares of the distances of the point (x, y, z) from the points (a, 0, 0) and (-a, 0, 0) is 2c^(2) , then which are of the following is correct?

Let P be the plane, which contains the line of intersection of the planes, x+y+z-6=0 and 2x+3y+z+5=0 and it is perpendicular to the XY-plane. Then, the distance of the point (0, 0, 256) from P is equal to

The perpendicular distance of the point (1,1,0) from the z-axis is -

Find the distance of the point (-6, 0, 0) from the plane 2x - 3y + 6z = 2.

Find the distance of the point (2, 0, 4) from the plane whose equation is x + y - 2z =0.

Find the distance of the point (2, 0, 4) from the plane whose equation is x + y - 2z =0.

Find the distance of the point (2, 1, 0) from the plane 2x + y + 2z + 5 = 0.