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A path 6 m wide runs around and outside ...

A path 6 m wide runs around and outside of a rectangular plot of length 10 m and breadth 8 m. The area (in `m^2`) of the path is:

A

440

B

600

C

80

D

360

Text Solution

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The correct Answer is:
To find the area of the path that runs around and outside a rectangular plot, we can follow these steps: ### Step 1: Find the dimensions of the inner rectangle The inner rectangle represents the plot itself. Given: - Length of the plot = 10 m - Breadth of the plot = 8 m ### Step 2: Calculate the area of the inner rectangle The area of a rectangle is calculated using the formula: \[ \text{Area} = \text{Length} \times \text{Breadth} \] Substituting the values: \[ \text{Area of inner rectangle} = 10 \, \text{m} \times 8 \, \text{m} = 80 \, \text{m}^2 \] ### Step 3: Determine the dimensions of the outer rectangle The path is 6 m wide and runs around the inner rectangle. Therefore, we need to add the width of the path to each dimension of the rectangle: - New length = Length of the plot + 2 × Width of the path \[ \text{New Length} = 10 \, \text{m} + 2 \times 6 \, \text{m} = 10 \, \text{m} + 12 \, \text{m} = 22 \, \text{m} \] - New breadth = Breadth of the plot + 2 × Width of the path \[ \text{New Breadth} = 8 \, \text{m} + 2 \times 6 \, \text{m} = 8 \, \text{m} + 12 \, \text{m} = 20 \, \text{m} \] ### Step 4: Calculate the area of the outer rectangle Using the dimensions of the outer rectangle: \[ \text{Area of outer rectangle} = \text{New Length} \times \text{New Breadth} \] Substituting the values: \[ \text{Area of outer rectangle} = 22 \, \text{m} \times 20 \, \text{m} = 440 \, \text{m}^2 \] ### Step 5: Calculate the area of the path The area of the path is the difference between the area of the outer rectangle and the area of the inner rectangle: \[ \text{Area of path} = \text{Area of outer rectangle} - \text{Area of inner rectangle} \] Substituting the values: \[ \text{Area of path} = 440 \, \text{m}^2 - 80 \, \text{m}^2 = 360 \, \text{m}^2 \] ### Final Answer The area of the path is **360 m²**.
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