Home
Class 14
MATHS
A pool has 3 taps. The first tap takes 3...

A pool has 3 taps. The first tap takes 3 days, the second tap takes 2 days, and the third tap takes 18 hours, to fill the pool. All the three taps are opened together. After 8 hours, the second tap is closed. The total time to fill the pool completely will be:

A

`128/11` hours

B

12 hours

C

`144/13` hours

D

4 hours

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Determine the filling rates of each tap. - **First tap**: Fills the pool in 3 days. - Rate = \( \frac{1 \text{ pool}}{3 \text{ days}} = \frac{1}{72} \text{ pools per hour} \) - **Second tap**: Fills the pool in 2 days. - Rate = \( \frac{1 \text{ pool}}{2 \text{ days}} = \frac{1}{48} \text{ pools per hour} \) - **Third tap**: Fills the pool in 18 hours. - Rate = \( \frac{1 \text{ pool}}{18 \text{ hours}} = \frac{1}{18} \text{ pools per hour} \) ### Step 2: Calculate the combined filling rate of all three taps. - Combined rate = Rate of first tap + Rate of second tap + Rate of third tap - Combined rate = \( \frac{1}{72} + \frac{1}{48} + \frac{1}{18} \) To add these fractions, we need a common denominator. The least common multiple (LCM) of 72, 48, and 18 is 144. - Convert each rate: - \( \frac{1}{72} = \frac{2}{144} \) - \( \frac{1}{48} = \frac{3}{144} \) - \( \frac{1}{18} = \frac{8}{144} \) - Now, add them: - Combined rate = \( \frac{2}{144} + \frac{3}{144} + \frac{8}{144} = \frac{13}{144} \text{ pools per hour} \) ### Step 3: Calculate the amount of the pool filled in the first 8 hours. - Amount filled in 8 hours = Combined rate × Time - Amount filled = \( \frac{13}{144} \times 8 = \frac{104}{144} = \frac{13}{18} \text{ of the pool} \) ### Step 4: Determine the remaining capacity of the pool. - Remaining capacity = 1 - Amount filled - Remaining capacity = \( 1 - \frac{13}{18} = \frac{5}{18} \text{ of the pool} \) ### Step 5: Calculate the new filling rate after the second tap is closed. - After 8 hours, only the first and third taps are open. - New combined rate = Rate of first tap + Rate of third tap - New combined rate = \( \frac{1}{72} + \frac{1}{18} \) Convert to a common denominator (which is 72): - \( \frac{1}{18} = \frac{4}{72} \) - New combined rate = \( \frac{1}{72} + \frac{4}{72} = \frac{5}{72} \text{ pools per hour} \) ### Step 6: Calculate the time required to fill the remaining capacity. - Time = Remaining capacity / New combined rate - Time = \( \frac{5/18}{5/72} = \frac{5}{18} \times \frac{72}{5} = 8 \text{ hours} \) ### Step 7: Calculate the total time to fill the pool. - Total time = Time for first 8 hours + Time for remaining capacity - Total time = \( 8 + 8 = 16 \text{ hours} \) Thus, the total time to fill the pool completely is **16 hours**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

A cistern can be filled by one tap in 4 hours and by another in 3hours.How long will it take to fill it if both taps are opened together?

If tap A can fill a tank 3 times faster than tap B and takes 28 min less than tap B to fill the tank. If both the taps are opened simultaneously, then find the time taken to fill the tank.

Three taps A, B and C can fill a tank in 20, 30 and 36 hours respectively. If all the taps are opened together, then in how many hours will the tank be filled?