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Two girls move in opposite directions, o...

Two girls move in opposite directions, one from A to B and the other from B to A. The girl from A reaches the destination in 12 minutes. The girl from B stops on the way for 10 minutes and reaches her destination in 25 minutes. If A's speed is 5 km/h, then what is the speed of B?

A

3km/h

B

`1 5/7` km/h

C

4km/h

D

2.4 km/h

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step-by-step, we will break down the information given and calculate the speed of the girl moving from B to A. ### Step 1: Understand the Information Given - The girl from A to B takes 12 minutes to reach her destination. - The girl from B to A takes 25 minutes in total but stops for 10 minutes on the way. - The speed of the girl from A to B is 5 km/h. ### Step 2: Convert Time from Minutes to Hours Since speed is given in km/h, we need to convert the time taken into hours. - For the girl from A to B: \[ \text{Time} = 12 \text{ minutes} = \frac{12}{60} \text{ hours} = \frac{1}{5} \text{ hours} \] ### Step 3: Calculate the Distance Between A and B Using the formula for distance: \[ \text{Distance} = \text{Speed} \times \text{Time} \] For the girl from A to B: \[ D = 5 \text{ km/h} \times \frac{1}{5} \text{ hours} = 1 \text{ km} \] ### Step 4: Analyze the Journey of the Girl from B to A The girl from B to A takes a total of 25 minutes, but she stops for 10 minutes. Therefore, the actual time she spends moving is: \[ \text{Moving Time} = 25 \text{ minutes} - 10 \text{ minutes} = 15 \text{ minutes} \] Convert this to hours: \[ \text{Moving Time} = \frac{15}{60} \text{ hours} = \frac{1}{4} \text{ hours} \] ### Step 5: Calculate the Speed of the Girl from B to A Using the distance calculated earlier (which is 1 km), we can find the speed of the girl from B to A: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} = \frac{1 \text{ km}}{\frac{1}{4} \text{ hours}} = 1 \text{ km} \times 4 = 4 \text{ km/h} \] ### Conclusion The speed of the girl moving from B to A is **4 km/h**. ---
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