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The radius of a spherical balloon increa...

The radius of a spherical balloon increases from 6 cm to 10 cm when more air is pumped into it. The ratio in the surface area of the original balloon and the inflated balloon is:

A

`4:5`

B

`27:125`

C

`3:5`

D

`9:25`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the surface area of the original balloon to the inflated balloon, we can follow these steps: ### Step 1: Understand the formula for the surface area of a sphere The surface area \( A \) of a sphere is given by the formula: \[ A = 4\pi r^2 \] where \( r \) is the radius of the sphere. ### Step 2: Calculate the surface area of the original balloon The original radius of the balloon is \( r_1 = 6 \) cm. Using the formula: \[ A_1 = 4\pi (6)^2 = 4\pi \times 36 = 144\pi \text{ cm}^2 \] ### Step 3: Calculate the surface area of the inflated balloon The inflated radius of the balloon is \( r_2 = 10 \) cm. Using the formula: \[ A_2 = 4\pi (10)^2 = 4\pi \times 100 = 400\pi \text{ cm}^2 \] ### Step 4: Find the ratio of the surface areas Now, we need to find the ratio of the surface area of the original balloon to the inflated balloon: \[ \text{Ratio} = \frac{A_1}{A_2} = \frac{144\pi}{400\pi} \] The \( \pi \) cancels out: \[ \text{Ratio} = \frac{144}{400} \] ### Step 5: Simplify the ratio To simplify \( \frac{144}{400} \), we can divide both the numerator and the denominator by their greatest common divisor (GCD), which is 16: \[ \frac{144 \div 16}{400 \div 16} = \frac{9}{25} \] ### Final Answer The ratio of the surface area of the original balloon to the inflated balloon is: \[ \boxed{9:25} \] ---
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