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A person increases his speed by 40 % .By...

A person increases his speed by 40 % .By doing so . He reaches his office 9 minutes before the usual time .How much time (in minutes)does he take usually to go to his office?

A

`31(1)/(2)`

B

33

C

32

D

`30(1)/(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these steps: ### Step 1: Understand the relationship between speed, time, and distance. When speed increases, the time taken to cover the same distance decreases. The relationship can be expressed as: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] This means that if speed increases, time decreases, and vice versa. ### Step 2: Define the variables. Let the usual time taken to reach the office be \( T \) minutes. Let the distance to the office be \( D \) and the usual speed be \( S \). Thus, we can express: \[ D = S \times T \] ### Step 3: Calculate the new speed after the increase. The speed is increased by 40%, so the new speed \( S' \) can be calculated as: \[ S' = S + 0.4S = 1.4S \] ### Step 4: Calculate the new time taken with the increased speed. The new time \( T' \) taken to reach the office with the new speed can be expressed as: \[ T' = \frac{D}{S'} = \frac{D}{1.4S} \] ### Step 5: Relate the new time to the usual time. Since the person reaches the office 9 minutes earlier, we can express this relationship as: \[ T' = T - 9 \] ### Step 6: Substitute the expression for \( T' \) into the equation. Substituting \( T' \) into the equation gives: \[ \frac{D}{1.4S} = T - 9 \] ### Step 7: Substitute \( D \) with \( S \times T \). Now substitute \( D = S \times T \) into the equation: \[ \frac{S \times T}{1.4S} = T - 9 \] This simplifies to: \[ \frac{T}{1.4} = T - 9 \] ### Step 8: Clear the fraction by multiplying through by 1.4. Multiplying both sides by 1.4 gives: \[ T = 1.4(T - 9) \] ### Step 9: Distribute and solve for \( T \). Expanding the right side: \[ T = 1.4T - 12.6 \] Now, rearranging gives: \[ 1.4T - T = 12.6 \] \[ 0.4T = 12.6 \] ### Step 10: Solve for \( T \). Dividing both sides by 0.4: \[ T = \frac{12.6}{0.4} = 31.5 \] ### Conclusion: The usual time taken to go to the office is \( 31.5 \) minutes. ---
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