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A sum of Rs. 8,235 is divided between A,...

A sum of Rs. 8,235 is divided between A,B, C and D such that the ratio of the shares of A and B is 3 : 4 that of B and C is 8 : 5 , and that of C and D is 7 : 10 .What is the difference between the shares of A and C ?

A

Rs. 270

B

Rs. 310

C

Rs. 405

D

Rs.315

Text Solution

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The correct Answer is:
To solve the problem, we need to find the shares of A, B, C, and D based on the given ratios and then calculate the difference between the shares of A and C. ### Step-by-Step Solution: 1. **Establish Ratios**: - The ratio of A to B is \(3:4\). - The ratio of B to C is \(8:5\). - The ratio of C to D is \(7:10\). 2. **Express Ratios in Terms of a Common Variable**: - Let the share of A be \(3x\) and the share of B be \(4x\) (from the ratio \(3:4\)). - From the ratio \(B:C = 8:5\), we can express B in terms of a new variable \(y\). Let \(B = 8y\) and \(C = 5y\). - Since \(B\) is the same in both ratios, we can equate \(4x = 8y\) which gives us \(x = 2y\). - Now substituting \(x\) back, we have: - \(A = 3x = 6y\) - \(B = 8y\) - \(C = 5y\) 3. **Express C and D**: - From the ratio \(C:D = 7:10\), let \(C = 7z\) and \(D = 10z\). - Since \(C = 5y\), we equate \(5y = 7z\) which gives us \(y = \frac{7z}{5}\). - Now substituting \(y\) back, we have: - \(A = 6y = 6 \times \frac{7z}{5} = \frac{42z}{5}\) - \(B = 8y = 8 \times \frac{7z}{5} = \frac{56z}{5}\) - \(C = 5y = 7z\) - \(D = 10z\) 4. **Total Shares**: - The total sum of shares is: \[ A + B + C + D = \frac{42z}{5} + \frac{56z}{5} + 7z + 10z \] - Converting \(7z\) and \(10z\) to a common denominator: \[ 7z = \frac{35z}{5}, \quad 10z = \frac{50z}{5} \] - Now adding them together: \[ \frac{42z}{5} + \frac{56z}{5} + \frac{35z}{5} + \frac{50z}{5} = \frac{183z}{5} \] 5. **Set Total Equal to Rs. 8235**: - We know the total is Rs. 8235, so: \[ \frac{183z}{5} = 8235 \] - Multiplying both sides by 5: \[ 183z = 41175 \] - Solving for \(z\): \[ z = \frac{41175}{183} = 225 \] 6. **Calculate Shares**: - Now substituting \(z\) back to find A, B, C, and D: - \(A = \frac{42 \times 225}{5} = 945\) - \(B = \frac{56 \times 225}{5} = 2520\) - \(C = 7 \times 225 = 1575\) - \(D = 10 \times 225 = 2250\) 7. **Find the Difference Between A and C**: - The difference between the shares of A and C is: \[ A - C = 945 - 1575 = -630 \] - Since we are interested in the absolute difference: \[ |A - C| = |945 - 1575| = 630 \] ### Final Answer: The difference between the shares of A and C is **630**.
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