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The simple interest on a certain sum for...

The simple interest on a certain sum for `4(2)/(3)` years at `6(3)/(4)%` is Rs 8,820. What will be the amount of the same sum after `7(1)/(2)` years at `8(1)/(3)%` at simple interest?

A

Rs 45, 500

B

Rs 45, 400

C

Rs 54, 500

D

Rs 54, 400

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will first find the principal amount (P) using the information provided about the simple interest for the first scenario, and then we will calculate the total amount after 7.5 years at a different interest rate. ### Step 1: Convert Mixed Numbers to Improper Fractions The time given is \(4 \frac{2}{3}\) years and the rate is \(6 \frac{3}{4}\%\). - Convert \(4 \frac{2}{3}\) to an improper fraction: \[ 4 \frac{2}{3} = \frac{4 \times 3 + 2}{3} = \frac{12 + 2}{3} = \frac{14}{3} \] - Convert \(6 \frac{3}{4}\%\) to a fraction: \[ 6 \frac{3}{4} = \frac{6 \times 4 + 3}{4} = \frac{24 + 3}{4} = \frac{27}{4} \] ### Step 2: Use the Simple Interest Formula The formula for simple interest (SI) is: \[ SI = \frac{P \times R \times T}{100} \] Where: - \(SI = 8820\) - \(R = \frac{27}{4}\) - \(T = \frac{14}{3}\) Substituting the values into the formula: \[ 8820 = \frac{P \times \frac{27}{4} \times \frac{14}{3}}{100} \] ### Step 3: Rearranging to Find P Rearranging the equation to solve for \(P\): \[ P = \frac{8820 \times 100}{\frac{27}{4} \times \frac{14}{3}} \] ### Step 4: Calculate the Denominator Calculating the denominator: \[ \frac{27}{4} \times \frac{14}{3} = \frac{27 \times 14}{4 \times 3} = \frac{378}{12} = 31.5 \] ### Step 5: Substitute Back to Find P Now substitute back to find \(P\): \[ P = \frac{8820 \times 100}{31.5} = \frac{882000}{31.5} \approx 28000 \] ### Step 6: Calculate Simple Interest for the New Scenario Now we need to find the amount after \(7 \frac{1}{2}\) years at \(8 \frac{1}{3}\%\). - Convert \(7 \frac{1}{2}\) to an improper fraction: \[ 7 \frac{1}{2} = \frac{7 \times 2 + 1}{2} = \frac{14 + 1}{2} = \frac{15}{2} \] - Convert \(8 \frac{1}{3}\%\) to a fraction: \[ 8 \frac{1}{3} = \frac{8 \times 3 + 1}{3} = \frac{24 + 1}{3} = \frac{25}{3} \] ### Step 7: Calculate the New Simple Interest Using the same simple interest formula: \[ SI = \frac{P \times R \times T}{100} \] Substituting the values: \[ SI = \frac{28000 \times \frac{25}{3} \times \frac{15}{2}}{100} \] ### Step 8: Calculate the Amount Calculating the new simple interest: \[ SI = \frac{28000 \times 25 \times 15}{3 \times 2 \times 100} = \frac{10500000}{600} = 17500 \] Now, the total amount \(A\) after \(7 \frac{1}{2}\) years: \[ A = P + SI = 28000 + 17500 = 45500 \] ### Final Answer The amount after \(7 \frac{1}{2}\) years at \(8 \frac{1}{3}\%\) is **Rs 45500**. ---
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