The profit earned by a company is to be divided among three friends who invested their money in the company, in the proportion of 6: 9:11. If the share of the person who invested the most is Rs. 2,310, then what is the sum of the money (in) received by the other two friends?

Options

A. 1890
B. 3150
C. 5460
D. 1260

Answer

To solve the problem, we need to follow these steps:

### Step 1: Understand the Ratio
The shares of the three friends are in the ratio of 6:9:11. Let's denote their shares as:
- Friend A: 6x
- Friend B: 9x
- Friend C: 11x

### Step 2: Identify the Highest Share
From the ratio, we can see that Friend C has the highest share, which is represented as 11x.

### Step 3: Set Up the Equation
According to the problem, the share of the person who invested the most (Friend C) is Rs. 2,310. Therefore, we can set up the equation:
\[ 11x = 2310 \]

### Step 4: Solve for x
To find the value of x, we divide both sides of the equation by 11:
\[ x = \frac{2310}{11} \]
Calculating this gives:
\[ x = 210 \]

### Step 5: Calculate the Shares of the Other Two Friends
Now that we have the value of x, we can calculate the shares of Friend A and Friend B:
- Friend A's share:
\[ 6x = 6 \times 210 = 1260 \]
- Friend B's share:
\[ 9x = 9 \times 210 = 1890 \]

### Step 6: Find the Sum of the Shares of the Other Two Friends
Now, we need to find the sum of the shares of Friend A and Friend B:
\[ \text{Sum} = 1260 + 1890 = 3150 \]

### Conclusion
The sum of the money received by the other two friends is Rs. 3150.