`int dx/sqrt((x-1)(x-2))`

Evaluate : intdx/sqrt((x-1)(2-x)) by the substitution x=1+sin^2theta . Hence, find the value of int_1^2dx/sqrt((x-1)(2-x))

int sqrt(2x-1) dx

int(x+1)sqrt((x+2)/(x-2))dx

int (x-1)sqrt(x+1)dx

Evaluate: int(dx)/(sqrt(1-x^2))

int(dx)/(sqrt(1-9x^(2)))

int(dx)/(sqrt(1-5x^(2)))

int sqrt(1+sin (x/2))dx

int sqrt(1+sin(x/2))dx=

int(dx)/(sqrt(1-x^(2))(sin^(-1)x)^(2))