(1) Find `(acostheta)/(bsintheta )+(bsintheta)/(acostheta)`

Find C

Find AD

Find x.

Find x.

(i) Find the equation a circle passing through the point (2+3costheta,1+3sintheta) where 'theta' is a parameter. (ii) Prove that the equations x=acostheta+bsintheta and y=asintheta-bcostheta represents a circle.

The value 2tan^(-1)[sqrt((a-b)/(a+b))tantheta/2] is equal to cos^(-1)((acostheta+b)/(a+bcostheta)) (b) cos^(-1)((a+bcostheta)/(acostheta+b)) cos^(-1)((acostheta)/(a+bcostheta)) (d) cos^(-1)((bcostheta)/(acostheta+b))

The value 2tan^(-1)[sqrt((a-b)/(a+b)tantheta/2)] is equal to cos^(-1)((acostheta+b)/(a+bcostheta)) (b) cos^(-1)((a+bcostheta)/(acostheta+b)) cos^(-1)((acostheta)/(a+bcostheta)) (d) cos^(-1)((bcostheta)/(acostheta+b))

If lim_(theta->0)((a(1-costheta))/(theta^2)-(bsintheta)/(theta))=1 then the value of 2b-a is -lambda , then the value of lambda is (1) 2 (2) 4 (3) 6 (4) 8

i) If acostheta+bsintheta=m and asintheta-bcostheta=n , then prove that: a^(2)+b^(2)=m^(2)+n^(2)