Home
Class 9
PHYSICS
"2" metre is the length of path travelle...

"2" metre is the length of path travelled by light in vacuum during a time interval of

`(1)/(299,972,458)` of a second

`(1)/(149,896,229)` of a second

`(1)/(149,896,427)` of a second

`(1)/(149,896,427)` of a second

Promotional Banner

Similar Questions

Explore conceptually related problems

The metre is defined as the distance travelled by ligh in (1)/(299,792,458) second. Why didn't people choose some easier number such as (1)/(300.000.000) second?

In the figure shown q is in coulomb and t in second. At time t=1 s

The length of a seconds pendulum is decreased by 1%. What is the gain or loss in time per day?

The position of an object moving on a straight line is defined by the relation x=t^(3)-2t^(2)-4t , where x is expressed in meter and t in second. Determine (a) the average velocity during the interval of 1 second to 4 second. (b) the velocity at t = 1 s and t = 4 s, (c) the average acceleration during the interval of 1 second to 4 second. (d) the acceleration at t = 4 s and t = 1 s.

A freely falling body traveled xm in n^(th) second distance travelled in n-1^(th) second is

The valency of helium is 2 because it is the second element of period 1.

If the unit of length is 16m and that of velocity is 24ms^(-1) , the unit of time is (in second)

If the unit of length is 4 m and that of velocity is 6 ms^(-1) , the unit of time is (in second)

A particle starts moving from rest such that it has uniform acceleration a_0 during the 1st second of motion, uniform acceleration (a_0)/(2) during the 2nd second of motion, uniform acceleration (a_0)/(4) during the 3rd second of motion, and so on, such that it has uniform acceleration (a_0)/(2^(n-1)) during the nth second of motion If the displacement of the particle during the 5th second of motion is D_5 =(Ka_0)/(32) , the value of K is

A freely falling body takes t second to travel (1//x)^(th) distance then time of descent is