Periodic time "t" of S H.M is given by

(a) `(2 pi)/(g)`

(b) `(2 pi)/(sqrt(w))`

(c) `A cos(sqrt(w)t+c)`

(d) None of these

If y=|cosx|+|sinx|,t h e n(dy)/(dx)a tx=(2pi)/3 is (1-sqrt(3))/2 (b) 0 (c) 1/2(sqrt(3)-1) (d) none of these

In Fig. 15.109, the area of segment A C B is (FIGURE) (a) (pi/3-(sqrt(3))/2)\ r^2 (b) (pi/3+(sqrt(3))/2)\ r^2 (c) (pi/3-2/(sqrt(3)))\ r^2 (d) None of these

The solution for x of the equation int_(sqrt(2))^x(dt)/(tsqrt(t^2-1))=pi/2 is pi (b) (sqrt(3))/2 (c) 2sqrt(2) (d) none of these

If x=tcost ,y=t+sint . Then (d^2 x)/(dy^2) at t=pi/2 is (a) (pi+4)/2 (b) -(pi+4)/2 (c) -2 (d) none of these

If sin^(-1)x-cos^(-1)x=pi/6 , then x= (a) 1/2 (b) (sqrt(3))/2 (c) -1/2 (d) none of these

If g(x)=int_0^x(|sint|+|cost|)dt ,t h e ng(x+(pin)/2) is equal to, where n in N , a) g(x)+g(pi) (b) g(x)+ng((pi)/(n2)) c) g(x)+g(pi/2) (d) none of these

Area bounded by the curve y=sqrt(sin[x]+[sinx]),(w h e r e[dot] is greatest integer function), lines x=1a d nx=pi/2a d bt h exa xi si s : (A) (sin1) pi/2-1 (B) sqrt(sin2.)(pi/2-1) (C) sqrt(cos1.)(pi/2-1) (D) none of these

sin^-1 (cos(sin^-1(sqrt(3)/2))= (A) pi/3 (B) pi/6 (C) - pi/6 (D) none of these

sqrt(3)int_0^pi dx/(1+2sin^2x)= (A) -pi (B) 0 (C) pi (D) none of these

sin^-1 (-1/2)+tan^-1 (sqrt(3))= (A) -pi/6 (B) pi/3 (C) pi/6 (D) none of these