` dy/dx`=`xy+x+y+1`

dy/dx = 2xy , y(0) = 1

Solve the following differential equations: (dy)/(dx)=1+x+y+x y (ii) y-x(dy)/(dx)=a(y^2+(dy)/(dx))

Solve the following differential equations: (dy)/(dx)=1+x+y+x y (ii) y-x(dy)/(dx)=a(y^2+(dy)/(dx))

Find dy/dx if y= xy

Statement 1: If e^(xy)+ln(xy)+cos(xy)+5=0, then (dy)/(dx)=-y/x . Statement 2: d/(dx)(xy)=0,y is a function of x implies(dy)/(dx)=-y/x .

Solve the following differential equations (dy)/(dx)=1+x+y+xy

The differential equations of all circle touching the x-axis at orgin is (a) (y^(2)-x^(2))=2xy((dy)/(dx)) (b) (x^(2)-y^(2))(dy)/(dx)=2xy ( c ) (x^(2)-y^(2))=2xy((dy)/(dx)) (d) None of these

xy=( x+y )^n and dy/dx = y/x then n= 1 b. 2 c. 3 d. 4

Suppose a solutions of the differential equation (xy^3 + x^2y^7) dy/dx =1 satisfies the initial conditions y(1/4)=1. Then the value of dy/dx when y = -1 is

Find dy/dx if x^2= 3xy