Solve `(sqrt3-sqrt2)/(sqrt3+sqrt2)=a-bsqrt6`

Solve (sqrt3-sqrt2)(2-sqrt2)

3/(sqrt3-sqrt2)=asqrt3-bsqrt2

Find rational numbers a and b such that (i) (sqrt2-1)/(sqrt2+1)=a+bsqrt2 (ii) (2-sqrt5)/(2+sqrt5)=asqrt5+b (iii) (sqrt3+sqrt2)/(sqrt3-sqrt2)=a+bsqrt6 (iv) (5+2sqrt3)/(7+4sqrt3)=a+bsqrt3

Solve (1/(sqrt3+sqrt2))+(1/(sqrt3-sqrt2))

Simplify (sqrt3+sqrt2)/(sqrt3+sqrt6)

(sqrt2+sqrt7)/(sqrt2-sqrt7)=a+bsqrt(14)

Solve (sqrt3 +sqrt2)^x + (sqrt3 -sqrt2)^x= 10 .

If a= (sqrt3 - sqrt2)/(sqrt3 + sqrt2), b = (sqrt3 + sqrt2)/(sqrt3 - sqrt2) then what is the value of a^2/b+b^2/a ?

Solve sqrt(2)sqrt(3)sqrt(5)