Hybridisation of `'P'` in the product obtained from reaction of `PH_(3)` with `HI` is
`sp^(3)`
`sp^(3)d`
`sp^(3)d^(2)`
Doesn't hybridise

sp^(3)d hybridisation has

Assertion: Transition metal ion forming octahedral complexes undergo sp^(3)d^(2) or d^(2) sp^(3) hybridisation. Reason: Strong field ligands force the unpaired electrons of central metal ion to pair up causingg d^(2)sp^(3) hybridisation whereas weak field ligands do not affect electronic configuration of the metal ion undergoes in sp^(3)d^(2) hybridisation.

Sulphur is sp^2 hybridised in

Which of the following complexes are not correctly matched with the hybridisation of their central metal ion ? (a) [Ni(CO)_4] , sp^(3) (b) [Ni(CN)_4]^(2-) , sp^(3) (c ) [CoF_6]^(3-) , d^(2)sp^(3) (d) [Fe(CN)_6]^(3-) , sp^(3)d^(2) Select the correct option :

The type of hybridisation of boron in diborane is (a) sp , (b) sp^(2) , (c) sp^(3) , (d) dsp^(2)

The type of hybridisation of boron in diborane is (a) sp , (b) sp^(2) , (c) sp^(3) , (d) dsp^(2)

Reduce the hybridisation, geometry and shape of the following (i) Br_(3)^(Θ) (ii) CIO_(3)^(o+) (iii) IO_(2)F_(2)^(Θ) Either of the hybridisation (i) sp^(2) and (ii) sp^(3)d^(2) of a central atom can lead to a squar planar molecule Give one example of each .

Which of the following compound have sp^(3)d^(2) hybridisation

sp^(3)d^(2) hybridization is not displayed by :

The d-orbitals involved in sp^(3)d hybridisation is: