Solve `(sqrt3+sqrt2)/(sqrt3-sqrt2)=a+bsqrt6`

Solve (sqrt3-sqrt2)(2-sqrt2)

Find rational numbers a and b such that (i) (sqrt2-1)/(sqrt2+1)=a+bsqrt2 (ii) (2-sqrt5)/(2+sqrt5)=asqrt5+b (iii) (sqrt3+sqrt2)/(sqrt3-sqrt2)=a+bsqrt6 (iv) (5+2sqrt3)/(7+4sqrt3)=a+bsqrt3

If a=(sqrt3+ sqrt2)/(sqrt3- sqrt2) and b=(sqrt3- sqrt2)/(sqrt3+sqrt2) , then what is the value of a^2+b^2-ab ?

3/(sqrt3-sqrt2)=asqrt3-bsqrt2

Solve (1/(sqrt3+sqrt2))+(1/(sqrt3-sqrt2))

Solve (sqrt3 +sqrt2)^x + (sqrt3 -sqrt2)^x= 10 .

(sqrt2+sqrt7)/(sqrt2-sqrt7)=a+bsqrt(14)

Simplify (sqrt3+sqrt2)/(sqrt3+sqrt6)

The square root of ( (sqrt3 + sqrt2)/(sqrt3 - sqrt2)) is