If equilibrium constant of reaction `2A(g)harr4B(g)` is `K` then equilibrium constant of `2B(g)harrA(g)` will be

If the equilibrium constant of the reaction 2HIhArr H_(2)+I_(2) is 0.25, then the equilibrium constant for the reaction, H_(2)(g)+I_(2)(g)hArr 2HI(g) would be

If the equilibrium constant of the reaction 2HI(g)hArrH_(2)(g)+I_(2)(g) is 0.25 , find the equilibrium constant of the reaction. (1)/(2)H_(2)+(1)/(2)I_(2)hArrHI(g)

In the equilibrium constant for N_(2)(g) + O_(2)(g)hArr2NO(g) is K, the equilibrium constant for (1)/(2) N_(2)(g) + (1)/(2)O_(2)(g)hArrNO(g) will be:

The equilibrium constant for the reaction A_(2)(g)+B_(2)(g) hArr 2AB(g) is 20 at 500K . The equilibrium constant for the reaction 2AB(g) hArr A_(2)(g)+B_(2)(g) would be

The value of equilibrium constant of the reaction. HI(g)hArr(1)/(2)H_2(g)+(1)/(2)I_2(g) is 8.0 The equilibrium constant of the reaction. H_2(g)+I_2(g)hArr2HI(g) will be

If the equilibrium constant for N_(2) (g) + O_(2)(g) hArr 2NO(g) is K , the equilibrium " constant for " 1/2 N_(2) (g) +1/2 O_(2) (g) hArr NO (g) will be

For the reaction N_2(g) +O_2( g) hArr 2NO(g), the equilibrium constant is K1 and for reaction 2NO(g) +O_2(g) hArr 2NO_2(g) . equilibrium constant is K2 What is K for the reaction NO_2(g) hArr (1)/(2) N_2(g) + O_2(g)

The value of equilibrium constant for the reaction [N_2O_5 (g) hArr 2NO_2(g) + 1/2 O_2(g)] is 0.5. The equilibruim constant for the reaction [4NO_2(g) + O_2(g) hArr 2N_2O_5(g)] is

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with

For the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) the equilibrium constant K_(p) changes with