A conductor with rectangular cross-section having dimensions 2a x 4a x 5a. If the resistance across AB is `R_1` across CD is `R_2` and across EF is `R_3` then the ratio `R_1`:`R_2`:`R_3` is

A conductor with rectangular cross section has dimensions (axx2axx4a) as shown in figure. Resistance across AB is x, across CD is y and across EF is z. Then

If the voltage across 500 Omega is 5 V. then R_2 is

The circuit has resistors of equal resistance R. The equivalent resistance between A and B, when key is closed is R_1 and when key is open is R_2 . Find the ratio R_1 and R_2 .

Relation between current in a conductor and time is shown in fig. If the resistance of the conductor is R, then the total heat disspipated across resistance R is

The dimensions of a conductor of specific resistance p are shown. Find the resistance of the conductor across AB, CD and EF.

The resistance of metal sheet 1 between A and B is R_1 and the resistance of sheet 2 between A' and B' is R_(2) . The value of the ratio (R_1)/(R_2) is

In the situation shown, resistance R_(1),R_(2) and R_(3) are in the ratio 3:2:1 , then

Two cells of emf E each and internal resistance r_(1) and r_(2) are connected in series across a load resistance R. If potential difference across the first cell is zero, then find the relation between R, r_(1) and r_(2)

Two cells of emf E each and internal resistance r_(1) and r_(2) are connected in series across a load resistance R. If potential difference across the first cell is zero, then find the relation between R, r_(1) and r_(2)

If E is the emf of a cell of internal resistance r and external resistance R, then potential difference across R is given as