Solve
`(2-sqrt5)/(2+sqrt5)=asqrt5+b`

Find rational numbers a and b such that (i) (sqrt2-1)/(sqrt2+1)=a+bsqrt2 (ii) (2-sqrt5)/(2+sqrt5)=asqrt5+b (iii) (sqrt3+sqrt2)/(sqrt3-sqrt2)=a+bsqrt6 (iv) (5+2sqrt3)/(7+4sqrt3)=a+bsqrt3

(5+sqrt7)(2+sqrt5)=?

find the values of a and b in each of the following (i) (5+2sqrt3)/(7+4sqrt3) = a-6sqrt3 (ii) (3-sqrt5)/(3+2sqrt5)= asqrt5-(19/11) (iii) (sqrt2+sqrt3)/(3sqrt2-2sqrt3)=2-bsqrt6 (iv) (7+sqrt5)/(7-sqrt5)-(7-sqrt5)/(7+sqrt5)=a+(7/11)bsqrt5

If both 'a' and 'b' are rational numbers, then 'a' and 'b' from (3-sqrt(5))/(3+2sqrt(5))=asqrt(5)-b , respectively are

Solve ((8+sqrt5)/(8-sqrt5))+((8-sqrt5)/(8+sqrt5))

Solve sqrt(2)sqrt(3)sqrt(5)

(2sqrt3+sqrt5)(2sqrt3+sqrt5)

(sqrt5 . sqrt2)

Find the values of a and b in each of the following : (a)(5+2sqrt3)/(7+4sqrt(3))=a-6sqrt(3)" "(b)(3-sqrt(5))/(3+2sqrt(5))=asqrt(5)-(19)/(11) (c )(sqrt(2)+sqrt(3))/(3sqrt2-2sqrt(3))=2-bsqrt(6)" "(d)(7+sqrt(5))/(7-sqrt(5))-(7-sqrt(5))/(7+sqrt(5))=a+(7)/(11)sqrt(5b)

Solve (sqrt(2))/(sqrt(2)+sqrt(3)-sqrt(5))