A body of mass 3 kg is under a constant force which causes a displacement s metre in it, given by the relation `s=(1)/(3)t^(2)`, where t is in seconds. Work done by the force in 2 seconds is
1 `5/19 J`
2 `3/8 J`
3 `8/3 J`
4 `19/5 J`

A body of mass 6kg is under a force which causes displacement in it given by S= (t^(2))/(4) maters where t is time . The work done by the force in 2 sec is

A body of mass 3 kg is under a force , which causes a displacement in it is given by S = (t^(3))/(3) (in metres). Find the work done by the force in first 2 seconds.

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A force F=(3thati + 5hatj)N acts on a body due to which its displacement varies as S=(2t^(2)hat-5hatj)m . Work done by these force in 2 s is .

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in metre and t in second. The work done by the force in the first two seconds is .

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in meter and t in second. The work done by the force in the first two seconds is .

The displacement of an object of mass 3 kg is given by the relation S=(1)/(3)t^(2) , where t is time in seconds. If the work done by the net force on the object in 2 s is (p)/(q) joule, where p and q are smallest integer values, then what is the value of p+q ?