The position of an object moving along x-axis is given by x = `2t + 3t ^2` and x is measured in metre and t in second. At what time the velocity of the object will be 20m/s?

The position of object moving along an x-axis is given by x=3t-4t^(2)+t^(3) , where x is in meters and t in seconds. Find the position of the object at the following values of t : (i) 2s, (ii) 4s, (iii) What is the object's displacement between t = 0 s and t = 4 s ? and (iv) What is its average vvelocity for the time interval from t = 2 s to t = 4 ?

The position of an object moving along x-axis is given by x=a +bt^(2) , where a=8.5 m and b=2.5 ms^(-2) and (t) is measured in seconds. What is the velocity at t=1= 0 s and t=2.0 s? What is the average velocity between t=2.0s and t=4.0 s ? a) 5 m/s b) 10 m/s c) 15 m/s d) 20 m/s

The position of and object moving along x-axis is given by x=a +bt^(2) , where a=8.5 m and b=2.5 ms^(-2) and (t) is measured in seconds. What is the velocity at t=0 s and t=2.0 s? What is the average velocity between t=2.0s and t=4.0 s ?

The position of the particle moving along Y -axis is given as y=At^(2)-Bt^(3) , where y is measured in metre and t in second. Then, the dimensions of B are

The position of the particle moving along Y -axis is given as y=At^(2)-Bt^(3) , where y is measured in metre and t in second. Then, the dimensions of B are

The position of an object moving along x-axis is given by x =a+bt^(2) where a =8.5 m, b=2.5 ms^(-2) and t is measured in seconds.Then which of the following is true ?

The position of and object moving along x-axis is gi en by x=a +bt^(2) , wher a=8.5 m and b=2.5 ms^(-2) and (t) is measured in ceconds. What is the velcoity at t=1= 0 s and t=2.0 s? What is the average velocity between t=2.0s and t=4.0 s ?

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

The position of a particle moving along x-axis is given by x = 10t - 2t^(2) . Then the time (t) at which it will momentily come to rest is

The position x of a particle with respect to time t along x-axis is given by x=9t^(2)−t^(3) where x is in metres and t is in seconds. What will be the position of this pariticle when it achieves maximum speed along the + x direction ?