Find the total distance travelled in minimum time taken by car that starts from rest and comes to rest after achieving a peak velocity of 16m/s while moving along a straight line. The magnitude of maximum acceleration and maximum retardation is same at 2m/`s^(2)`.

A body starts from rest and travels a distance x with uniform acceleration, then it travels a distance 2x with uniform speed, finally it travels a distance 3x with uniform retardation and comes to rest. If the complete motion of the particle is along a straight line, then the ratio of its average velocity to maximum velocity is

A particle, initially at rest, starts moving in a straight line with an acceleration a=6t+4 m//s^(2) . The distance covered by it in 3 s is

A body with initial velocity 8 m/s moves along a straight line with constant acceleration and travels 640 m in 40 s. For the 40 s interval, find the average velocity

A bullet travelling with a velocity of 16 m/s penetrates a tree trunk and comes to rest in 0.4 m. Find the time taken during the retardation.

The acceleration of a particle starting from rest and travelling along a straight line is shown in figure. The maximum speed of the particle is

A particle starts with a velocity of 2m//s and moves in a straight line with a retardation of 0.1m//s^(2) . The time that it takes to describe 15m is

A particle starts from rest at time t=0 and moves on a straight line with acceleration as plotted in fig. The speed of the particle will be maximum after time.

A body starts from rest and acquires a velocity 10 m s^(-1) in 2 s. Find the acceleration.

A car is travelling on a road. The maximum velocity the car can attain is 24 ms^-1 and the maximum deceleration is 4 ms^-2. If car starts from rest and comes to rest after travelling 1032m in the shortest time of 56 s, the maximum acceleration that the car can attain is