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A 270-m long train takes 24 seconds to c...

A 270-m long train takes 24 seconds to cross a pole. If it takes 1 minute to cross a tunnel, then the length (in m ) of the tunnel is :

A

507

B

405

C

408

D

510

Text Solution

AI Generated Solution

The correct Answer is:
To find the length of the tunnel that the train crosses, we can follow these steps: ### Step 1: Calculate the speed of the train. The speed of the train can be calculated using the formula: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] Here, the distance is the length of the train, which is 270 meters, and the time taken to cross a pole is 24 seconds. \[ \text{Speed} = \frac{270 \text{ m}}{24 \text{ s}} = \frac{270}{24} \text{ m/s} \] ### Step 2: Simplify the speed calculation. To simplify \( \frac{270}{24} \): - Divide both the numerator and the denominator by 3: \[ \frac{270 \div 3}{24 \div 3} = \frac{90}{8} \] - Now, divide both by 2: \[ \frac{90 \div 2}{8 \div 2} = \frac{45}{4} \text{ m/s} \] ### Step 3: Set up the equation for crossing the tunnel. When the train crosses the tunnel, it travels a distance equal to its own length plus the length of the tunnel (let's denote the length of the tunnel as \( X \)): \[ \text{Distance} = 270 + X \] The time taken to cross the tunnel is given as 1 minute, which is equal to 60 seconds. ### Step 4: Use the speed to find the length of the tunnel. Using the speed we calculated, we can set up the equation: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] Substituting the known values: \[ \frac{45}{4} = \frac{270 + X}{60} \] ### Step 5: Solve for \( X \). Cross-multiplying gives: \[ 45 \times 60 = 4 \times (270 + X) \] Calculating \( 45 \times 60 \): \[ 2700 = 4 \times (270 + X) \] Now, divide both sides by 4: \[ 675 = 270 + X \] Subtract 270 from both sides: \[ X = 675 - 270 = 405 \] ### Conclusion: The length of the tunnel is \( 405 \) meters. ---
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