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A, B and C can complete a work in 16, 24...

A, B and C can complete a work in 16, 24 and 32 days, respectively. They started together but C left after 4 days of starting and A left 6 days before completion of the work. In how many days will the work be completed ?

A

9 days

B

15 days

C

12 days

D

14 days

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will first determine the work rates of A, B, and C, and then calculate how much work is done before C leaves and how much is done after that. ### Step 1: Determine the work rates of A, B, and C. - A can complete the work in 16 days, so A's work rate is \( \frac{1}{16} \) of the work per day. - B can complete the work in 24 days, so B's work rate is \( \frac{1}{24} \) of the work per day. - C can complete the work in 32 days, so C's work rate is \( \frac{1}{32} \) of the work per day. ### Step 2: Calculate the combined work rate of A, B, and C. To find the combined work rate, we add their individual work rates: \[ \text{Combined work rate} = \frac{1}{16} + \frac{1}{24} + \frac{1}{32} \] To add these fractions, we need a common denominator. The least common multiple (LCM) of 16, 24, and 32 is 96. Now, we convert each fraction: - \( \frac{1}{16} = \frac{6}{96} \) - \( \frac{1}{24} = \frac{4}{96} \) - \( \frac{1}{32} = \frac{3}{96} \) Adding these together: \[ \text{Combined work rate} = \frac{6}{96} + \frac{4}{96} + \frac{3}{96} = \frac{13}{96} \] ### Step 3: Calculate the work done in the first 4 days. In the first 4 days, A, B, and C work together: \[ \text{Work done in 4 days} = 4 \times \frac{13}{96} = \frac{52}{96} = \frac{13}{24} \] ### Step 4: Determine the remaining work. The total work is 1 (whole work), so the remaining work after 4 days is: \[ \text{Remaining work} = 1 - \frac{13}{24} = \frac{24 - 13}{24} = \frac{11}{24} \] ### Step 5: Calculate the work rate after C leaves. After 4 days, C leaves, so only A and B continue to work. Their combined work rate is: \[ \text{A's work rate} + \text{B's work rate} = \frac{1}{16} + \frac{1}{24} \] Using the common denominator of 48: - \( \frac{1}{16} = \frac{3}{48} \) - \( \frac{1}{24} = \frac{2}{48} \) Thus, the combined work rate of A and B is: \[ \frac{3}{48} + \frac{2}{48} = \frac{5}{48} \] ### Step 6: Calculate the time taken to finish the remaining work. Let \( t \) be the time taken by A and B to complete the remaining work \( \frac{11}{24} \): \[ \frac{5}{48} \times t = \frac{11}{24} \] To solve for \( t \): \[ t = \frac{11}{24} \div \frac{5}{48} = \frac{11}{24} \times \frac{48}{5} = \frac{11 \times 2}{5} = \frac{22}{5} = 4.4 \text{ days} \] ### Step 7: Calculate the total time taken to complete the work. The total time taken is the initial 4 days plus the time taken by A and B to finish the remaining work: \[ \text{Total time} = 4 + 4.4 = 8.4 \text{ days} \] ### Final Answer: The work will be completed in **8.4 days**.
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