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A certain sum of money becomes 4 times i...

A certain sum of money becomes 4 times in 12 years when invested at simple interest. In how many years will it become 10 times of itself at the same rate?

A

60

B

48

C

24

D

36

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine how long it will take for a sum of money to become 10 times itself when invested at simple interest, given that it becomes 4 times in 12 years. ### Step-by-Step Solution: 1. **Understanding Simple Interest**: The formula for simple interest is given by: \[ A = P + SI \] where \( A \) is the total amount after time \( t \), \( P \) is the principal amount (initial investment), and \( SI \) is the simple interest earned. 2. **Identifying the Initial Condition**: We know that the sum of money becomes 4 times itself in 12 years. This means: \[ A = 4P \] Therefore, the simple interest earned in 12 years can be expressed as: \[ SI = A - P = 4P - P = 3P \] 3. **Using the Simple Interest Formula**: We can express the simple interest in terms of the principal, rate, and time: \[ SI = \frac{P \times r \times t}{100} \] where \( r \) is the rate of interest and \( t \) is the time in years. For our case: \[ SI = \frac{P \times r \times 12}{100} \] Setting the two expressions for simple interest equal gives: \[ 3P = \frac{P \times r \times 12}{100} \] 4. **Solving for the Rate of Interest**: Dividing both sides by \( P \) (assuming \( P \neq 0 \)): \[ 3 = \frac{r \times 12}{100} \] Rearranging this gives: \[ r = \frac{3 \times 100}{12} = 25 \] So, the rate of interest \( r \) is 25%. 5. **Finding Time to Become 10 Times**: Now we want to find out how long it will take for the sum to become 10 times itself: \[ A = 10P \] The simple interest in this case would be: \[ SI = A - P = 10P - P = 9P \] Using the simple interest formula again: \[ 9P = \frac{P \times r \times t}{100} \] Substituting \( r = 25 \): \[ 9P = \frac{P \times 25 \times t}{100} \] Dividing both sides by \( P \): \[ 9 = \frac{25t}{100} \] Rearranging gives: \[ t = \frac{9 \times 100}{25} = 36 \] ### Final Answer: Thus, it will take **36 years** for the sum of money to become 10 times itself at the same rate of interest.
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