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A shopkeeper placed a supply order for j...

A shopkeeper placed a supply order for jeans, shirts and t-shirts at the rates of Rs. 500, Rs.350 and Rs.200 per piece, respectively. He buys articles of each type in the ratio 1:2:3 for Rs. 46,800. For how many t-shirts did he place the order?

A

104

B

26

C

78

D

52

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find out how many t-shirts the shopkeeper ordered based on the given information. ### Step 1: Define Variables Let: - The number of jeans ordered = \( x \) - The number of shirts ordered = \( 2x \) (since the ratio is 1:2:3) - The number of t-shirts ordered = \( 3x \) ### Step 2: Calculate the Total Cost The cost of each type of clothing is given as follows: - Cost of jeans = Rs. 500 per piece - Cost of shirts = Rs. 350 per piece - Cost of t-shirts = Rs. 200 per piece Now, we can express the total cost based on the quantities: \[ \text{Total Cost} = (\text{Cost of jeans}) + (\text{Cost of shirts}) + (\text{Cost of t-shirts}) \] \[ = 500x + 350(2x) + 200(3x) \] ### Step 3: Simplify the Total Cost Expression Substituting the values: \[ = 500x + 700x + 600x \] \[ = (500 + 700 + 600)x = 1800x \] ### Step 4: Set Up the Equation According to the problem, the total cost is Rs. 46,800. Therefore, we can set up the equation: \[ 1800x = 46800 \] ### Step 5: Solve for \( x \) To find \( x \), divide both sides of the equation by 1800: \[ x = \frac{46800}{1800} \] \[ x = 26 \] ### Step 6: Calculate the Number of T-shirts Since the number of t-shirts ordered is \( 3x \): \[ \text{Number of t-shirts} = 3x = 3 \times 26 = 78 \] ### Final Answer The shopkeeper placed an order for **78 t-shirts**. ---
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