If sintheta=acosphiandcostheta=b sinphi...

If `sintheta=acosphiandcostheta=b sinphi` then the value of `(a^(2)-1)cot^(2)phi+(1-b^(2))cot^(2)theta` is equal to :

A

`(a^2 + b^2)/a^2`

B

`(a^2 + b^2)/b^2`

C

`(a^2 -b^2)/b^2`

D

`(a^2 - b^2)/a^2`

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The correct Answer is:

A, B

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