(tantheta+cottheta)/(tantheta-cottheta)=...

`(tantheta+cottheta)/(tantheta-cottheta)=2,(0lt=thetalt=9 0^(@))` then the value of `sintheta` is

A

`(2)/(sqrt(3))`

B

`(sqrt(3))/(2)`

C

`(1)/(2)`

D

1

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