Home
Class 9
MATHS
A piece of rectangular cardboard sheet m...

A piece of rectangular cardboard sheet measuring 40 inch `xx25` inch is made into an open chocolate box by cutting out squares of side 'p' from each corner. Which of the following expressions is equivalent to the volume of the box ?

A

`4p^(3)-120p^(2)+950p`

B

`4p^(3)+130p^(2)+1000p`

C

`4p^(3)-130p^(2)+1000p`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the volume of the open chocolate box made from the rectangular cardboard sheet, we follow these steps: ### Step 1: Understand the dimensions of the cardboard The dimensions of the cardboard sheet are given as: - Length = 40 inches - Width = 25 inches ### Step 2: Identify the squares cut from each corner We are cutting out squares of side 'p' from each corner of the cardboard. This will affect the dimensions of the box. ### Step 3: Calculate the new dimensions of the box After cutting out squares of side 'p', the new dimensions of the box will be: - **Length of the box**: \[ \text{Length} = 40 - 2p \] (since we cut 'p' from both ends of the length) - **Width of the box**: \[ \text{Width} = 25 - 2p \] (since we cut 'p' from both ends of the width) ### Step 4: Determine the height of the box The height of the box will be equal to the side of the square cut out, which is: \[ \text{Height} = p \] ### Step 5: Write the formula for the volume of the box The volume \( V \) of a box (cuboid) is given by the formula: \[ V = \text{Length} \times \text{Width} \times \text{Height} \] Substituting the dimensions we found: \[ V = (40 - 2p)(25 - 2p)(p) \] ### Step 6: Expand the volume expression Now we will expand this expression: 1. First, expand the first two terms: \[ (40 - 2p)(25 - 2p) = 40 \times 25 - 40 \times 2p - 25 \times 2p + 2p \times 2p \] \[ = 1000 - 80p - 50p + 4p^2 \] \[ = 1000 - 130p + 4p^2 \] 2. Now multiply this result by \( p \): \[ V = (1000 - 130p + 4p^2)(p) \] \[ = 1000p - 130p^2 + 4p^3 \] ### Step 7: Write the final volume expression Rearranging the terms, we get: \[ V = 4p^3 - 130p^2 + 1000p \] ### Final Answer The expression equivalent to the volume of the box is: \[ V = 4p^3 - 130p^2 + 1000p \]
Promotional Banner

Topper's Solved these Questions

  • IMO QUESTION PAPER 2018 SET B

    SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section |5 Videos
  • IMO QUESTION PAPER 2018 SET B

    SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section |5 Videos
  • IMO QUESTION PAPER 2018 SET A

    SCIENCE OLYMPIAD FOUNDATION |Exercise ACHIEVERS SECTION|5 Videos
  • IMO QUESTION PAPER 2020 SET 1

    SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section|5 Videos

Similar Questions

Explore conceptually related problems

A rectangular piece of cardboard 18cm xx24cm is made into an open box by cutting a square of 5cm side from each corner and building up the side.Find the volume of the box in cu.cm.(a) 216 (b) 432 (c) 560 (d) None of these

A rectangular sheet of tin 45cm by 24cm is to be made into a box without top,by cutting off square from each corner and folding up the flaps.What should be the side of the square to be cut off so that the volume of the box is maximum?

A rectangular sheet of tin 45cm by 24cm is to be made into a box without top,by cutting off squares from each corners and folding up the flaps.What should be the side of the square to be cut off so that the volume of the box is maximum possible?

A rectangular sheet of tin 58 cmxx44cm is to be made into an open box by cutting off equal squares from the corners and folding up the flaps.What should be the volume of box if the surface area of box is 2452 cm^(2) ?

A square piece of tin of side 18cm is to be made into a box without top by cutting a square from each corner and folding up the flaps to form a box.What should be the side of the square to be cut off so that the volume of the box is maximum? Also,find the maximum volume.

A square piece of tin of side 24 cm is to be made into a box without top by cutting a square from each corner and foding up the flaps to form a box. What should be the side of the square to be cut off so that the volume of the box is maximum ? Also, find this maximum volume.

A square piece of tin of side 18cm is to be made into a box without top,by cutting a square from each corner and folding up the flaps to form the box.What should be the side of the square to be cut off so that the volume of the box is the maximum possible?

A square piece of tin of side 12 cm is to be made into a box without a lid by cutting a square from each corner and folding up the flaps to form the sides. What should be the side of the square to be cut off so that the volume of the box is maximum ? Also, find this maximum volume