The ratio of the number of molecules in 4 g of hydrogen to the number of molecules in 5.6 `dm^3` of oxygen at standard temperature and pressure is [Given: Atomic mass of H = 1 u and O = 16 u]
A
`2:1`
B
`3:4`
C
`1:4`
D
`8:1`
Text Solution
AI Generated Solution
The correct Answer is:
To solve the problem, we need to find the ratio of the number of molecules in 4 g of hydrogen to the number of molecules in 5.6 dm³ of oxygen at standard temperature and pressure (STP).
### Step 1: Calculate the number of moles of hydrogen
- The molecular formula for hydrogen gas is H₂.
- The molecular mass of H₂ = 2 × Atomic mass of H = 2 × 1 u = 2 g/mol.
- Given mass of hydrogen = 4 g.
Using the formula for moles:
\[
\text{Number of moles of H₂} = \frac{\text{Given mass}}{\text{Molecular mass}} = \frac{4 \text{ g}}{2 \text{ g/mol}} = 2 \text{ moles}
\]
### Step 2: Calculate the number of molecules of hydrogen
- Using Avogadro's number (6.022 × 10²³ molecules/mol), we can find the number of molecules in 2 moles of hydrogen:
\[
\text{Number of molecules of H₂} = 2 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} = 12.044 \times 10^{23} \text{ molecules}
\]
### Step 3: Calculate the number of moles of oxygen
- The molecular formula for oxygen gas is O₂.
- The molecular mass of O₂ = 2 × Atomic mass of O = 2 × 16 u = 32 g/mol.
- At STP, 1 mole of any gas occupies 22.4 L (or 22.4 dm³).
- Given volume of oxygen = 5.6 dm³.
Using the formula for moles:
\[
\text{Number of moles of O₂} = \frac{\text{Volume}}{22.4 \text{ dm³/mol}} = \frac{5.6 \text{ dm³}}{22.4 \text{ dm³/mol}} = 0.25 \text{ moles}
\]
### Step 4: Calculate the number of molecules of oxygen
- Using Avogadro's number:
\[
\text{Number of molecules of O₂} = 0.25 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} = 1.5055 \times 10^{23} \text{ molecules}
\]
### Step 5: Calculate the ratio of the number of molecules of hydrogen to oxygen
\[
\text{Ratio} = \frac{\text{Number of molecules of H₂}}{\text{Number of molecules of O₂}} = \frac{12.044 \times 10^{23}}{1.5055 \times 10^{23}} \approx 8
\]
### Final Answer
The ratio of the number of molecules in 4 g of hydrogen to the number of molecules in 5.6 dm³ of oxygen at standard temperature and pressure is approximately **8:1**.
---
Topper's Solved these Questions
NSO QUESTION PAPER 2017 SET B
SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section|2 Videos
NSO QUESTION PAPER 2017 SET A
SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section|2 Videos
NSO QUESTION PAPER 2018 SET A
SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section|2 Videos
Similar Questions
Explore conceptually related problems
Calculate the number of molecules in 4 g of oxygen .
16 g of oxygen have same number of molecules as in :
The number of air molecules in a (5m xx 5m xx 4m) room at standard temperature and pressure is of the order of
The number of molecules is 16 g of oxygen gas is ____________
The number of O_3 molecules in 16 g of ozone is approximately.
Calculate the number of molecules in each of the following : 124 g of phosphorus Given atomic masses : P = 31 u, C = 12 u, O = 16 u
A vessel contains two non-reactive gases neon (monoatomic) and oxygen (diatomic). The ratio of their partial pressures is 3:2. Estimate the ratio of (i) number of molecules, and (ii) mass density of neon and oxygen in the vessel. Atomic mass of neon = 20.2 u, and molecular mass of oxygen = 32.0 u.
SCIENCE OLYMPIAD FOUNDATION -NSO QUESTION PAPER 2017 SET B-Achievers Section