`int_-1^2(2x+1)(x-2)dx`

Evaluate: int_1^2 1/((x+1)(x+2))dx (ii) int_1^2 1/(x(1+x^2))dx

int_(-1)^(1)e^(2x)dx

int_-1^1(x^2-3x+2)dx

The value of the integral int_(-1)^(1) (x-[2x]) dx,is

Evaluate: int_0^4 1/(x+sqrt(x))dx (ii) int_0^1(2x)/(5x^2+1)dx

int_(-1)^2 (x/4+1/2)dx-int_-1^2x^2/4 dx

int_(-1)^2 (x/4+1/2)dx-int_-1^2x^2/4 dx

Let I_(1)=int_(1)^(2)(x)/(sqrt(1+x^(2)))dx and I_(2)=int_(1)^(2)(1)/(x)dx .Then

int_(-1)^2 ((x+2)/4)dx-int_-1^2x^2/4 dx

If I_(1)=int_(0)^(1) 2^(x^(2)) dx, I_(2)=int_(0)^(1) 2^(x^(3)) dx, I_(3)=int_(1)^(2) 2^(x^(2))dx and I_(4)=int_(1)^(2) 2^(x^(3))dx then